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202011055531 is a prime number
BaseRepresentation
bin1011110000100011001…
…1000001010110101011
3201022102111102220001121
42330020303001112223
511302204312234111
6232445210000111
720411010432445
oct2741063012653
9638374386047
10202011055531
1178743a79a6a
1233199116037
1316084b6766c
149ac5217495
1553c4cbc871
hex2f08cc15ab

202011055531 has 2 divisors, whose sum is σ = 202011055532. Its totient is φ = 202011055530.

The previous prime is 202011055529. The next prime is 202011055577. The reversal of 202011055531 is 135550110202.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 202011055531 - 21 = 202011055529 is a prime.

It is a super-2 number, since 2×2020110555312 (a number of 23 digits) contains 22 as substring.

Together with 202011055529, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 202011055496 and 202011055505.

It is not a weakly prime, because it can be changed into another prime (202011055501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101005527765 + 101005527766.

It is an arithmetic number, because the mean of its divisors is an integer number (101005527766).

Almost surely, 2202011055531 is an apocalyptic number.

202011055531 is a deficient number, since it is larger than the sum of its proper divisors (1).

202011055531 is an equidigital number, since it uses as much as digits as its factorization.

202011055531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 202011055531 its reverse (135550110202), we get a palindrome (337561165733).

The spelling of 202011055531 in words is "two hundred two billion, eleven million, fifty-five thousand, five hundred thirty-one".