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20202000212103 = 343735121303857
BaseRepresentation
bin1001001011111101001010…
…00010111110000010000111
32122112021220010111111022220
410211332211002332002013
510121442144023241403
6110544400515423423
74153355253343023
oct445764502760207
978467803444286
1020202000212103
116489690500196
122323348bb4b73
13b3706ab22968
144dbad3c51383
15250778c10953
hex125fa50be087

20202000212103 has 16 divisors (see below), whose sum is σ = 27566169666816. Its totient is φ = 13153000694400.

The previous prime is 20202000212077. The next prime is 20202000212117. The reversal of 20202000212103 is 30121200020202.

It is a happy number.

It is not a de Polignac number, because 20202000212103 - 212 = 20202000208007 is a prime.

It is a super-3 number, since 3×202020002121033 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20202000212183) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9703650 + ... + 11600207.

It is an arithmetic number, because the mean of its divisors is an integer number (1722885604176).

Almost surely, 220202000212103 is an apocalyptic number.

20202000212103 is a deficient number, since it is larger than the sum of its proper divisors (7364169454713).

20202000212103 is a wasteful number, since it uses less digits than its factorization.

20202000212103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21311254.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 20202000212103 its reverse (30121200020202), we get a palindrome (50323200232305).

The spelling of 20202000212103 in words is "twenty trillion, two hundred two billion, two hundred twelve thousand, one hundred three".

Divisors: 1 3 43 129 7351 22053 316093 948279 21303857 63911571 916065851 2748197553 156604652807 469813958421 6734000070701 20202000212103