Base | Representation |
---|---|
bin | 11101011010001101100… |
… | …101010100100010101111 |
3 | 21011012120122212102210222 |
4 | 131122031211110202233 |
5 | 231103012030000142 |
6 | 4144234510121555 |
7 | 266004340362353 |
oct | 35321545244257 |
9 | 7135518772728 |
10 | 2021010000047 |
11 | 70a118503895 |
12 | 2878281b02bb |
13 | 11877126aa6c |
14 | 6db62d67463 |
15 | 37887752bd2 |
hex | 1d68d9548af |
2021010000047 has 2 divisors, whose sum is σ = 2021010000048. Its totient is φ = 2021010000046.
The previous prime is 2021009999999. The next prime is 2021010000091. The reversal of 2021010000047 is 7400000101202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2021010000047 - 216 = 2021009934511 is a prime.
It is a super-3 number, since 3×20210100000473 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2021010000547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010505000023 + 1010505000024.
It is an arithmetic number, because the mean of its divisors is an integer number (1010505000024).
Almost surely, 22021010000047 is an apocalyptic number.
2021010000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021010000047 is an equidigital number, since it uses as much as digits as its factorization.
2021010000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 17.
Adding to 2021010000047 its reverse (7400000101202), we get a palindrome (9421010101249).
The spelling of 2021010000047 in words is "two trillion, twenty-one billion, ten million, forty-seven", and thus it is an aban number and an uban number.
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