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20211110102143 is a prime number
BaseRepresentation
bin1001001100001110001000…
…00010011100010001111111
32122120011102000100212010201
410212013010002130101333
510122114323141232033
6110552504504144331
74154130102210142
oct446070402342177
978504360325121
1020211110102143
116492535828434
12232506ba680a7
13b37b9029a23c
144dc319ab0059
15250b0d89747d
hex1261c409c47f

20211110102143 has 2 divisors, whose sum is σ = 20211110102144. Its totient is φ = 20211110102142.

The previous prime is 20211110102077. The next prime is 20211110102243. The reversal of 20211110102143 is 34120101111202.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20211110102143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20211110102143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20211110102243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105555051071 + 10105555051072.

It is an arithmetic number, because the mean of its divisors is an integer number (10105555051072).

Almost surely, 220211110102143 is an apocalyptic number.

20211110102143 is a deficient number, since it is larger than the sum of its proper divisors (1).

20211110102143 is an equidigital number, since it uses as much as digits as its factorization.

20211110102143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 20211110102143 its reverse (34120101111202), we get a palindrome (54331211213345).

The spelling of 20211110102143 in words is "twenty trillion, two hundred eleven billion, one hundred ten million, one hundred two thousand, one hundred forty-three".