20211110147 has 2 divisors, whose sum is σ = 20211110148. Its totient is φ = 20211110146.

The previous prime is 20211110119. The next prime is 20211110149. The reversal of 20211110147 is 74101111202.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20211110147 - 2¹⁰ = 20211109123 is a prime.

Together with 20211110149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20211110149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105555073 + 10105555074.

It is an arithmetic number, because the mean of its divisors is an integer number (10105555074).

Almost surely, 2^20211110147 is an apocalyptic number.

20211110147 is a deficient number, since it is larger than the sum of its proper divisors (1).

20211110147 is an equidigital number, since it uses as much as digits as its factorization.

20211110147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 20211110147 its reverse (74101111202), we get a palindrome (94312221349).

The spelling of 20211110147 in words is "twenty billion, two hundred eleven million, one hundred ten thousand, one hundred forty-seven".