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20211210112013 is a prime number
BaseRepresentation
bin1001001100001110010011…
…11111111100110000001101
32122120011122222112212212222
410212013021333330300031
510122120024242041023
6110552522435505125
74154132425243124
oct446071177746015
978504588485788
1020211210112013
116492587226318
1223250994581a5
13b37ba7c1538b
144dc3290a4abb
15250b1754ecc8
hex1261c9ffcc0d

20211210112013 has 2 divisors, whose sum is σ = 20211210112014. Its totient is φ = 20211210112012.

The previous prime is 20211210111941. The next prime is 20211210112021. The reversal of 20211210112013 is 31021101211202.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16967166050884 + 3244044061129 = 4119122^2 + 1801123^2 .

It is a cyclic number.

It is not a de Polignac number, because 20211210112013 - 212 = 20211210107917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20211210111982 and 20211210112000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20211210612013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105605056006 + 10105605056007.

It is an arithmetic number, because the mean of its divisors is an integer number (10105605056007).

Almost surely, 220211210112013 is an apocalyptic number.

It is an amenable number.

20211210112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

20211210112013 is an equidigital number, since it uses as much as digits as its factorization.

20211210112013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 20211210112013 its reverse (31021101211202), we get a palindrome (51232311323215).

The spelling of 20211210112013 in words is "twenty trillion, two hundred eleven billion, two hundred ten million, one hundred twelve thousand, thirteen".