Base | Representation |
---|---|
bin | 101101111101001000100000… |
… | …110010011111101100110010 |
3 | 222111121211021220211100221020 |
4 | 231331020200302133230302 |
5 | 202442410133001414442 |
6 | 1553505252552440310 |
7 | 60400122361435416 |
oct | 5575104062375462 |
9 | 874554256740836 |
10 | 202113121123122 |
11 | 59443769883240 |
12 | 1a802a633a9096 |
13 | 88a1254832861 |
14 | 37ca481dccd46 |
15 | 185765d1819ec |
hex | b7d220c9fb32 |
202113121123122 has 32 divisors (see below), whose sum is σ = 441738335709504. Its totient is φ = 61140254054400.
The previous prime is 202113121123099. The next prime is 202113121123187. The reversal of 202113121123122 is 221321121311202.
It is a junction number, because it is equal to n+sod(n) for n = 202113121123092 and 202113121123101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2653618779 + ... + 2653694942.
It is an arithmetic number, because the mean of its divisors is an integer number (13804322990922).
Almost surely, 2202113121123122 is an apocalyptic number.
202113121123122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
202113121123122 is an abundant number, since it is smaller than the sum of its proper divisors (239625214586382).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
202113121123122 is a wasteful number, since it uses less digits than its factorization.
202113121123122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5307314314.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 202113121123122 its reverse (221321121311202), we get a palindrome (423434242434324).
The spelling of 202113121123122 in words is "two hundred two trillion, one hundred thirteen billion, one hundred twenty-one million, one hundred twenty-three thousand, one hundred twenty-two".
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