Base | Representation |
---|---|
bin | 1011110000111011100… |
… | …0011010111100000101 |
3 | 201022200121112000212021 |
4 | 2330032320122330011 |
5 | 11302411430244331 |
6 | 232503253523141 |
7 | 20413360203346 |
oct | 2741670327405 |
9 | 638617460767 |
10 | 202113134341 |
11 | 78796660318 |
12 | 332073434b1 |
13 | 160a0058421 |
14 | 9ad49ca0cd |
15 | 53cdc33211 |
hex | 2f0ee1af05 |
202113134341 has 2 divisors, whose sum is σ = 202113134342. Its totient is φ = 202113134340.
The previous prime is 202113134303. The next prime is 202113134347. The reversal of 202113134341 is 143431311202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 158287805316 + 43825329025 = 397854^2 + 209345^2 .
It is a cyclic number.
It is not a de Polignac number, because 202113134341 - 215 = 202113101573 is a prime.
It is a super-2 number, since 2×2021131343412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (202113134347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101056567170 + 101056567171.
It is an arithmetic number, because the mean of its divisors is an integer number (101056567171).
Almost surely, 2202113134341 is an apocalyptic number.
It is an amenable number.
202113134341 is a deficient number, since it is larger than the sum of its proper divisors (1).
202113134341 is an equidigital number, since it uses as much as digits as its factorization.
202113134341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 202113134341 its reverse (143431311202), we get a palindrome (345544445543).
The spelling of 202113134341 in words is "two hundred two billion, one hundred thirteen million, one hundred thirty-four thousand, three hundred forty-one".
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