Search a number
-
+
202120133 is a prime number
BaseRepresentation
bin11000000110000…
…01101111000101
3112002022202200212
430003001233011
5403220321013
632020045205
75002664345
oct1403015705
9462282625
10202120133
11a4100936
1257833805
1332b4a317
141cbb4d25
1512b276a8
hexc0c1bc5

202120133 has 2 divisors, whose sum is σ = 202120134. Its totient is φ = 202120132.

The previous prime is 202120129. The next prime is 202120141. The reversal of 202120133 is 331021202.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102779044 + 99341089 = 10138^2 + 9967^2 .

It is a cyclic number.

It is not a de Polignac number, because 202120133 - 22 = 202120129 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202120103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101060066 + 101060067.

It is an arithmetic number, because the mean of its divisors is an integer number (101060067).

Almost surely, 2202120133 is an apocalyptic number.

It is an amenable number.

202120133 is a deficient number, since it is larger than the sum of its proper divisors (1).

202120133 is an equidigital number, since it uses as much as digits as its factorization.

202120133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 202120133 is about 14216.8960395721. The cubic root of 202120133 is about 586.8627239799.

Adding to 202120133 its reverse (331021202), we get a palindrome (533141335).

The spelling of 202120133 in words is "two hundred two million, one hundred twenty thousand, one hundred thirty-three".