Base | Representation |
---|---|
bin | 1001001100010001110111… |
… | …10101101000101111101111 |
3 | 2122120100121002100211002122 |
4 | 10212020323311220233233 |
5 | 10122132432210324442 |
6 | 110553440143343155 |
7 | 4154230646152352 |
oct | 446107365505757 |
9 | 78510532324078 |
10 | 20213120011247 |
11 | 6493377322939 |
12 | 2325530bb1abb |
13 | b38120803977 |
14 | 4dc46a9c8299 |
15 | 250bca065dd2 |
hex | 12623bd68bef |
20213120011247 has 2 divisors, whose sum is σ = 20213120011248. Its totient is φ = 20213120011246.
The previous prime is 20213120011171. The next prime is 20213120011261. The reversal of 20213120011247 is 74211002131202.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20213120011247 - 214 = 20213119994863 is a prime.
It is a super-3 number, since 3×202131200112473 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20213120014247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10106560005623 + 10106560005624.
It is an arithmetic number, because the mean of its divisors is an integer number (10106560005624).
Almost surely, 220213120011247 is an apocalyptic number.
20213120011247 is a deficient number, since it is larger than the sum of its proper divisors (1).
20213120011247 is an equidigital number, since it uses as much as digits as its factorization.
20213120011247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 20213120011247 its reverse (74211002131202), we get a palindrome (94424122142449).
The spelling of 20213120011247 in words is "twenty trillion, two hundred thirteen billion, one hundred twenty million, eleven thousand, two hundred forty-seven".
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