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20221100201213 is a prime number
BaseRepresentation
bin1001001100100000101110…
…11111101001010011111101
32122121010012020111110201222
410212100113133221103331
510122300303122414323
6111001240054443125
74154632466514332
oct446202737512375
978533166443658
1020221100201213
1164967a199a75a
122326b996634a5
13b38ac2bcbc72
144dc9c67b6989
15250ee594b9c8
hex1264177e94fd

20221100201213 has 2 divisors, whose sum is σ = 20221100201214. Its totient is φ = 20221100201212.

The previous prime is 20221100201173. The next prime is 20221100201233. The reversal of 20221100201213 is 31210200112202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19974803385124 + 246296816089 = 4469318^2 + 496283^2 .

It is a cyclic number.

It is not a de Polignac number, because 20221100201213 - 218 = 20221099939069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20221100201191 and 20221100201200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20221100201233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10110550100606 + 10110550100607.

It is an arithmetic number, because the mean of its divisors is an integer number (10110550100607).

Almost surely, 220221100201213 is an apocalyptic number.

It is an amenable number.

20221100201213 is a deficient number, since it is larger than the sum of its proper divisors (1).

20221100201213 is an equidigital number, since it uses as much as digits as its factorization.

20221100201213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 20221100201213 its reverse (31210200112202), we get a palindrome (51431300313415).

The spelling of 20221100201213 in words is "twenty trillion, two hundred twenty-one billion, one hundred million, two hundred one thousand, two hundred thirteen".