Base | Representation |
---|---|
bin | 11101011011010100100… |
… | …001001110110000111101 |
3 | 21011022122121021021221121 |
4 | 131123110201032300331 |
5 | 231112431212011031 |
6 | 4144552542230541 |
7 | 266046001220161 |
oct | 35332441166075 |
9 | 7138577237847 |
10 | 2022200110141 |
11 | 70a679275152 |
12 | 287aba885451 |
13 | 1189009ab813 |
14 | 6dc37040ca1 |
15 | 37906e88011 |
hex | 1d6d484ec3d |
2022200110141 has 2 divisors, whose sum is σ = 2022200110142. Its totient is φ = 2022200110140.
The previous prime is 2022200110129. The next prime is 2022200110291. The reversal of 2022200110141 is 1410110022202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1176673884516 + 845526225625 = 1084746^2 + 919525^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022200110141 - 223 = 2022191721533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2022200110841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011100055070 + 1011100055071.
It is an arithmetic number, because the mean of its divisors is an integer number (1011100055071).
Almost surely, 22022200110141 is an apocalyptic number.
It is an amenable number.
2022200110141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022200110141 is an equidigital number, since it uses as much as digits as its factorization.
2022200110141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 2022200110141 its reverse (1410110022202), we get a palindrome (3432310132343).
The spelling of 2022200110141 in words is "two trillion, twenty-two billion, two hundred million, one hundred ten thousand, one hundred forty-one".
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