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202220111211997 is a prime number
BaseRepresentation
bin101101111110101100001001…
…111001010010110111011101
3222112000001110020120000110111
4231332230021321102313131
5203001133241432240442
61554030345301410021
760410630604253654
oct5576541171226735
9875001406500414
10202220111211997
1159485081a0359a
121a81b742109911
1388ab375587c58
1437d171154a19b
15185a320dc8b17
hexb7eb09e52ddd

202220111211997 has 2 divisors, whose sum is σ = 202220111211998. Its totient is φ = 202220111211996.

The previous prime is 202220111211941. The next prime is 202220111212003. The reversal of 202220111211997 is 799112111022202.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 186648358648761 + 15571752563236 = 13661931^2 + 3946106^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-202220111211997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202220111211907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101110055605998 + 101110055605999.

It is an arithmetic number, because the mean of its divisors is an integer number (101110055605999).

Almost surely, 2202220111211997 is an apocalyptic number.

It is an amenable number.

202220111211997 is a deficient number, since it is larger than the sum of its proper divisors (1).

202220111211997 is an equidigital number, since it uses as much as digits as its factorization.

202220111211997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 40.

The spelling of 202220111211997 in words is "two hundred two trillion, two hundred twenty billion, one hundred eleven million, two hundred eleven thousand, nine hundred ninety-seven".