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2022322014133 is a prime number
BaseRepresentation
bin11101011011011011110…
…010010000011110110101
321011022222002122122210021
4131123123302100132311
5231113203413423013
64145013015125141
7266052011331331
oct35333362203665
97138862578707
102022322014133
1170a731067453
12287b336737b1
13118920021265
146dc492d47c1
1537912a17a8d
hex1d6dbc907b5

2022322014133 has 2 divisors, whose sum is σ = 2022322014134. Its totient is φ = 2022322014132.

The previous prime is 2022322014101. The next prime is 2022322014151. The reversal of 2022322014133 is 3314102232202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1529459044369 + 492862969764 = 1236713^2 + 702042^2 .

It is a cyclic number.

It is not a de Polignac number, because 2022322014133 - 25 = 2022322014101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2022322014098 and 2022322014107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2022322014173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011161007066 + 1011161007067.

It is an arithmetic number, because the mean of its divisors is an integer number (1011161007067).

Almost surely, 22022322014133 is an apocalyptic number.

It is an amenable number.

2022322014133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2022322014133 is an equidigital number, since it uses as much as digits as its factorization.

2022322014133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 2022322014133 its reverse (3314102232202), we get a palindrome (5336424246335).

The spelling of 2022322014133 in words is "two trillion, twenty-two billion, three hundred twenty-two million, fourteen thousand, one hundred thirty-three".