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2023010110141 is a prime number
BaseRepresentation
bin11101011100000100110…
…011001000101010111101
321011101202001102120001121
4131130010303020222331
5231121111042011031
64145205155310541
7266105035133206
oct35340463105275
97141661376047
102023010110141
1170aa54516139
122880a5bab451
131189cc753267
146dcb28505ad
1537953138011
hex1d704cc8abd

2023010110141 has 2 divisors, whose sum is σ = 2023010110142. Its totient is φ = 2023010110140.

The previous prime is 2023010110139. The next prime is 2023010110159. The reversal of 2023010110141 is 1410110103202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1959521229241 + 63488880900 = 1399829^2 + 251970^2 .

It is a cyclic number.

It is not a de Polignac number, because 2023010110141 - 21 = 2023010110139 is a prime.

Together with 2023010110139, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023010110111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011505055070 + 1011505055071.

It is an arithmetic number, because the mean of its divisors is an integer number (1011505055071).

Almost surely, 22023010110141 is an apocalyptic number.

It is an amenable number.

2023010110141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023010110141 is an equidigital number, since it uses as much as digits as its factorization.

2023010110141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2023010110141 its reverse (1410110103202), we get a palindrome (3433120213343).

The spelling of 2023010110141 in words is "two trillion, twenty-three billion, ten million, one hundred ten thousand, one hundred forty-one".