Base | Representation |
---|---|
bin | 10010110101110111… |
… | …001001010010100011 |
3 | 1221012221012100101122 |
4 | 102311313021102203 |
5 | 312413114020001 |
6 | 13143300322455 |
7 | 1314225446636 |
oct | 226567112243 |
9 | 57187170348 |
10 | 20231001251 |
11 | 864196674a |
12 | 3b073a342b |
13 | 1ba54c7876 |
14 | d9cc57c1d |
15 | 7d619ab1b |
hex | 4b5dc94a3 |
20231001251 has 2 divisors, whose sum is σ = 20231001252. Its totient is φ = 20231001250.
The previous prime is 20231001223. The next prime is 20231001253. The reversal of 20231001251 is 15210013202.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20231001251 - 226 = 20163892387 is a prime.
Together with 20231001253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20231001253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115500625 + 10115500626.
It is an arithmetic number, because the mean of its divisors is an integer number (10115500626).
Almost surely, 220231001251 is an apocalyptic number.
20231001251 is a deficient number, since it is larger than the sum of its proper divisors (1).
20231001251 is an equidigital number, since it uses as much as digits as its factorization.
20231001251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 20231001251 its reverse (15210013202), we get a palindrome (35441014453).
The spelling of 20231001251 in words is "twenty billion, two hundred thirty-one million, one thousand, two hundred fifty-one".
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