Search a number
-
+
2023110431 is a prime number
BaseRepresentation
bin111100010010110…
…0011011100011111
312012222211122202222
41320211203130133
513120404013211
6532430135555
7101064104066
oct17045433437
95188748688
102023110431
11948aa18a1
124856515bb
132631a9484
141529931dd
15bc92a1db
hex7896371f

2023110431 has 2 divisors, whose sum is σ = 2023110432. Its totient is φ = 2023110430.

The previous prime is 2023110407. The next prime is 2023110433. The reversal of 2023110431 is 1340113202.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2023110431 is a prime.

It is a super-2 number, since 2×20231104312 = 8185951632042011522, which contains 22 as substring.

Together with 2023110433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023110433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011555215 + 1011555216.

It is an arithmetic number, because the mean of its divisors is an integer number (1011555216).

Almost surely, 22023110431 is an apocalyptic number.

2023110431 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023110431 is an equidigital number, since it uses as much as digits as its factorization.

2023110431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2023110431 is about 44978.9998888370. Note that the first 3 decimals coincide. The cubic root of 2023110431 is about 1264.7553633385.

Adding to 2023110431 its reverse (1340113202), we get a palindrome (3363223633).

The spelling of 2023110431 in words is "two billion, twenty-three million, one hundred ten thousand, four hundred thirty-one".