Base | Representation |
---|---|
bin | 10010110101111000… |
… | …101101111000010111 |
3 | 1221012221222021120122 |
4 | 102311320231320113 |
5 | 312413220211041 |
6 | 13143313222155 |
7 | 1314232114106 |
oct | 226570557027 |
9 | 57187867518 |
10 | 20231413271 |
11 | 8642118263 |
12 | 3b0756195b |
13 | 1ba5610274 |
14 | d9cd2403d |
15 | 7d622cc4b |
hex | 4b5e2de17 |
20231413271 has 2 divisors, whose sum is σ = 20231413272. Its totient is φ = 20231413270.
The previous prime is 20231413201. The next prime is 20231413273. The reversal of 20231413271 is 17231413202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20231413271 - 210 = 20231412247 is a prime.
Together with 20231413273, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20231413271.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20231413273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115706635 + 10115706636.
It is an arithmetic number, because the mean of its divisors is an integer number (10115706636).
Almost surely, 220231413271 is an apocalyptic number.
20231413271 is a deficient number, since it is larger than the sum of its proper divisors (1).
20231413271 is an equidigital number, since it uses as much as digits as its factorization.
20231413271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 20231413271 its reverse (17231413202), we get a palindrome (37462826473).
The spelling of 20231413271 in words is "twenty billion, two hundred thirty-one million, four hundred thirteen thousand, two hundred seventy-one".
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