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20231475533981 is a prime number
BaseRepresentation
bin1001001100110100000011…
…11010011001100010011101
32122122002222022111222121222
410212122001322121202131
510122433030214041411
6111010113410103125
74155450552423035
oct446320172314235
978562868458558
1020231475533981
1164a0136561838
122328bb427aaa5
13b39a875a211a
144dd2cc71c8c5
152514017494db
hex126681e9989d

20231475533981 has 2 divisors, whose sum is σ = 20231475533982. Its totient is φ = 20231475533980.

The previous prime is 20231475533911. The next prime is 20231475533993. The reversal of 20231475533981 is 18933557413202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19895926435225 + 335549098756 = 4460485^2 + 579266^2 .

It is a cyclic number.

It is not a de Polignac number, because 20231475533981 - 218 = 20231475271837 is a prime.

It is a super-3 number, since 3×202314755339813 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20231475533911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115737766990 + 10115737766991.

It is an arithmetic number, because the mean of its divisors is an integer number (10115737766991).

Almost surely, 220231475533981 is an apocalyptic number.

It is an amenable number.

20231475533981 is a deficient number, since it is larger than the sum of its proper divisors (1).

20231475533981 is an equidigital number, since it uses as much as digits as its factorization.

20231475533981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5443200, while the sum is 53.

The spelling of 20231475533981 in words is "twenty trillion, two hundred thirty-one billion, four hundred seventy-five million, five hundred thirty-three thousand, nine hundred eighty-one".