Base | Representation |
---|---|
bin | 11101011100011101111… |
… | …001000111110110011100 |
3 | 21011102211101121120100121 |
4 | 131130131321013312130 |
5 | 231122441331010134 |
6 | 4145315035004324 |
7 | 266121336440161 |
oct | 35343571076634 |
9 | 7142741546317 |
10 | 2023431110044 |
11 | 710150124643 |
12 | 2881a2b996a4 |
13 | 118a68a38126 |
14 | 6dd12720068 |
15 | 3797a098ab4 |
hex | 1d71de47d9c |
2023431110044 has 12 divisors (see below), whose sum is σ = 3599053696168. Its totient is φ = 995130054000.
The previous prime is 2023431110039. The next prime is 2023431110167. The reversal of 2023431110044 is 4400111343202.
It is a super-3 number, since 3×20234311100443 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4146374982 + ... + 4146375469.
Almost surely, 22023431110044 is an apocalyptic number.
It is an amenable number.
2023431110044 is a deficient number, since it is larger than the sum of its proper divisors (1575622586124).
2023431110044 is a wasteful number, since it uses less digits than its factorization.
2023431110044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8292750516 (or 8292750514 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2023431110044 its reverse (4400111343202), we get a palindrome (6423542453246).
The spelling of 2023431110044 in words is "two trillion, twenty-three billion, four hundred thirty-one million, one hundred ten thousand, forty-four".
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