Base | Representation |
---|---|
bin | 1011110100010100100… |
… | …0111100000100011101 |
3 | 201102001001102001020221 |
4 | 2331011020330010131 |
5 | 11311242444342023 |
6 | 233133452441341 |
7 | 20445052500301 |
oct | 2750510740435 |
9 | 642031361227 |
10 | 203023434013 |
11 | 791134879a4 |
12 | 33420179251 |
13 | 161b6819b9a |
14 | 9b7d867d01 |
15 | 5433ae685d |
hex | 2f4523c11d |
203023434013 has 2 divisors, whose sum is σ = 203023434014. Its totient is φ = 203023434012.
The previous prime is 203023433983. The next prime is 203023434079. The reversal of 203023434013 is 310434320302.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 201706977924 + 1316456089 = 449118^2 + 36283^2 .
It is a cyclic number.
It is not a de Polignac number, because 203023434013 - 217 = 203023302941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (203023432013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101511717006 + 101511717007.
It is an arithmetic number, because the mean of its divisors is an integer number (101511717007).
Almost surely, 2203023434013 is an apocalyptic number.
It is an amenable number.
203023434013 is a deficient number, since it is larger than the sum of its proper divisors (1).
203023434013 is an equidigital number, since it uses as much as digits as its factorization.
203023434013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 203023434013 its reverse (310434320302), we get a palindrome (513457754315).
The spelling of 203023434013 in words is "two hundred three billion, twenty-three million, four hundred thirty-four thousand, thirteen".
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