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2030440034141 is a prime number
BaseRepresentation
bin11101100010111111101…
…010000010111101011101
321012002220212010210200222
4131202333222002331131
5231231320122043031
64152434332331125
7266460124345211
oct35427752027535
97162825123628
102030440034141
11713117513aa2
1228961a313aa5
13119614b46cac
14703b9520941
1537c3a576e7b
hex1d8bfa82f5d

2030440034141 has 2 divisors, whose sum is σ = 2030440034142. Its totient is φ = 2030440034140.

The previous prime is 2030440034131. The next prime is 2030440034143. The reversal of 2030440034141 is 1414300440302.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1272575767225 + 757864266916 = 1128085^2 + 870554^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2030440034141 is a prime.

Together with 2030440034143, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2030440034141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2030440034143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015220017070 + 1015220017071.

It is an arithmetic number, because the mean of its divisors is an integer number (1015220017071).

Almost surely, 22030440034141 is an apocalyptic number.

It is an amenable number.

2030440034141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2030440034141 is an equidigital number, since it uses as much as digits as its factorization.

2030440034141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 2030440034141 its reverse (1414300440302), we get a palindrome (3444740474443).

The spelling of 2030440034141 in words is "two trillion, thirty billion, four hundred forty million, thirty-four thousand, one hundred forty-one".