203111314220041 has 2 divisors, whose sum is σ = 203111314220042. Its totient is φ = 203111314220040.

The previous prime is 203111314220039. The next prime is 203111314220051. The reversal of 203111314220041 is 140022413111302.

203111314220041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 166263075644416 + 36848238575625 = 12894304^2 + 6070275^2 .

It is a cyclic number.

It is not a de Polignac number, because 203111314220041 - 2¹ = 203111314220039 is a prime.

Together with 203111314220039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 203111314219988 and 203111314220015.

It is not a weakly prime, because it can be changed into another prime (203111314220051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101555657110020 + 101555657110021.

It is an arithmetic number, because the mean of its divisors is an integer number (101555657110021).

Almost surely, 2^{203111314220041} is an apocalyptic number.

It is an amenable number.

203111314220041 is a deficient number, since it is larger than the sum of its proper divisors (1).

203111314220041 is an equidigital number, since it uses as much as digits as its factorization.

203111314220041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 203111314220041 its reverse (140022413111302), we get a palindrome (343133727331343).

The spelling of 203111314220041 in words is "two hundred three trillion, one hundred eleven billion, three hundred fourteen million, two hundred twenty thousand, forty-one".