Base | Representation |
---|---|
bin | 10010111010101001… |
… | …011101011110100000 |
3 | 1221102112021221120101 |
4 | 102322221131132200 |
5 | 313044143100000 |
6 | 13155245352144 |
7 | 1316222126035 |
oct | 227251353640 |
9 | 57375257511 |
10 | 20311300000 |
11 | 8683221352 |
12 | 3b2a268654 |
13 | 1bb9030c14 |
14 | da979b38c |
15 | 7dd25ce6a |
hex | 4baa5d7a0 |
20311300000 has 144 divisors (see below), whose sum is σ = 52160661504. Its totient is φ = 7770400000.
The previous prime is 20311299997. The next prime is 20311300007. The reversal of 20311300000 is 311302.
It is a Harshad number since it is a multiple of its sum of digits (10).
It is a self number, because there is not a number n which added to its sum of digits gives 20311300000.
It is not an unprimeable number, because it can be changed into a prime (20311300007) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2295585 + ... + 2304415.
It is an arithmetic number, because the mean of its divisors is an integer number (362226816).
Almost surely, 220311300000 is an apocalyptic number.
20311300000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 20311300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26080330752).
20311300000 is an abundant number, since it is smaller than the sum of its proper divisors (31849361504).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20311300000 is an frugal number, since it uses more digits than its factorization.
20311300000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8889 (or 8861 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 10.
Adding to 20311300000 its reverse (311302), we get a palindrome (20311611302).
It can be divided in two parts, 2031 and 1300000, that added together give a palindrome (1302031).
The spelling of 20311300000 in words is "twenty billion, three hundred eleven million, three hundred thousand".
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