203113240001130 has 64 divisors (see below), whose sum is σ = 487801160985600. Its totient is φ = 54126934953984.

The previous prime is 203113240001107. The next prime is 203113240001137. The reversal of 203113240001130 is 31100042311302.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 203113240001097 and 203113240001106.

It is not an unprimeable number, because it can be changed into a prime (203113240001137) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1581211146 + ... + 1581339594.

It is an arithmetic number, because the mean of its divisors is an integer number (7621893140400).

Almost surely, 2^{203113240001130} is an apocalyptic number.

203113240001130 is an abundant number, since it is smaller than the sum of its proper divisors (284687920984470).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

203113240001130 is a wasteful number, since it uses less digits than its factorization.

203113240001130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163663.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 203113240001130 its reverse (31100042311302), we get a palindrome (234213282312432).

The spelling of 203113240001130 in words is "two hundred three trillion, one hundred thirteen billion, two hundred forty million, one thousand, one hundred thirty".