Base | Representation |
---|---|
bin | 11101100110100000011… |
… | …100101010111100010011 |
3 | 21012110122200122010010012 |
4 | 131212200130222330103 |
5 | 231312031104321431 |
6 | 4154300454025135 |
7 | 266652440422253 |
oct | 35464034527423 |
9 | 7173580563105 |
10 | 2034211401491 |
11 | 714782339115 |
12 | 28a2b13481ab |
13 | 119a962978c9 |
14 | 7065635b963 |
15 | 37dab6d922b |
hex | 1d9a072af13 |
2034211401491 has 2 divisors, whose sum is σ = 2034211401492. Its totient is φ = 2034211401490.
The previous prime is 2034211401329. The next prime is 2034211401493. The reversal of 2034211401491 is 1941041124302.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2034211401491 is a prime.
Together with 2034211401493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2034211401493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1017105700745 + 1017105700746.
It is an arithmetic number, because the mean of its divisors is an integer number (1017105700746).
Almost surely, 22034211401491 is an apocalyptic number.
2034211401491 is a deficient number, since it is larger than the sum of its proper divisors (1).
2034211401491 is an equidigital number, since it uses as much as digits as its factorization.
2034211401491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 32.
Adding to 2034211401491 its reverse (1941041124302), we get a palindrome (3975252525793).
The spelling of 2034211401491 in words is "two trillion, thirty-four billion, two hundred eleven million, four hundred one thousand, four hundred ninety-one".
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