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20350214431 is a prime number
BaseRepresentation
bin10010111100111101…
…111010000100011111
31221112020112000010121
4102330331322010133
5313134123330211
613203155415411
71320203653141
oct227475720437
957466460117
1020350214431
1186a3190338
123b3b2b4567
131bc4107601
14db0a0ac91
157e1898271
hex4bcf7a11f

20350214431 has 2 divisors, whose sum is σ = 20350214432. Its totient is φ = 20350214430.

The previous prime is 20350214419. The next prime is 20350214447. The reversal of 20350214431 is 13441205302.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20350214431 - 27 = 20350214303 is a prime.

It is a super-2 number, since 2×203502144312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20350214396 and 20350214405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20350214411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10175107215 + 10175107216.

It is an arithmetic number, because the mean of its divisors is an integer number (10175107216).

Almost surely, 220350214431 is an apocalyptic number.

20350214431 is a deficient number, since it is larger than the sum of its proper divisors (1).

20350214431 is an equidigital number, since it uses as much as digits as its factorization.

20350214431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 20350214431 its reverse (13441205302), we get a palindrome (33791419733).

The spelling of 20350214431 in words is "twenty billion, three hundred fifty million, two hundred fourteen thousand, four hundred thirty-one".