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20411565265141 is a prime number
BaseRepresentation
bin1001010010000011100000…
…00110001101000011110101
32200021022211002010012212221
410221001300012031003311
510133410341201441031
6111224535454042341
74204454421036031
oct451016006150365
980238732105787
1020411565265141
11655a5505112a6
122357a93aa93b1
13b50a579a311b
14507cd43d51c1
15255e41c79a11
hex12907018d0f5

20411565265141 has 2 divisors, whose sum is σ = 20411565265142. Its totient is φ = 20411565265140.

The previous prime is 20411565265139. The next prime is 20411565265151. The reversal of 20411565265141 is 14156256511402.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19592397268900 + 819167996241 = 4426330^2 + 905079^2 .

It is a cyclic number.

It is not a de Polignac number, because 20411565265141 - 21 = 20411565265139 is a prime.

It is a super-3 number, since 3×204115652651413 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 20411565265139, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20411565265151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10205782632570 + 10205782632571.

It is an arithmetic number, because the mean of its divisors is an integer number (10205782632571).

Almost surely, 220411565265141 is an apocalyptic number.

It is an amenable number.

20411565265141 is a deficient number, since it is larger than the sum of its proper divisors (1).

20411565265141 is an equidigital number, since it uses as much as digits as its factorization.

20411565265141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 43.

The spelling of 20411565265141 in words is "twenty trillion, four hundred eleven billion, five hundred sixty-five million, two hundred sixty-five thousand, one hundred forty-one".