Base | Representation |
---|---|
bin | 1001010010000110011101… |
… | …10100100000000111010111 |
3 | 2200021110220211110200120012 |
4 | 10221003032310200013113 |
5 | 10133422120020210434 |
6 | 111225401304030435 |
7 | 4204541666004401 |
oct | 451031664400727 |
9 | 80243824420505 |
10 | 20413154460119 |
11 | 6560196582a83 |
12 | 235825816241b |
13 | b50c4bcc4a95 |
14 | 5080054b5b71 |
15 | 255ed65423ce |
hex | 1290ced201d7 |
20413154460119 has 2 divisors, whose sum is σ = 20413154460120. Its totient is φ = 20413154460118.
The previous prime is 20413154460103. The next prime is 20413154460121. The reversal of 20413154460119 is 91106445131402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20413154460119 - 24 = 20413154460103 is a prime.
It is a super-3 number, since 3×204131544601193 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 20413154460121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20413154460169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10206577230059 + 10206577230060.
It is an arithmetic number, because the mean of its divisors is an integer number (10206577230060).
Almost surely, 220413154460119 is an apocalyptic number.
20413154460119 is a deficient number, since it is larger than the sum of its proper divisors (1).
20413154460119 is an equidigital number, since it uses as much as digits as its factorization.
20413154460119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 41.
The spelling of 20413154460119 in words is "twenty trillion, four hundred thirteen billion, one hundred fifty-four million, four hundred sixty thousand, one hundred nineteen".
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