Base | Representation |
---|---|
bin | 101110011011101101011001… |
… | …100110001101011000001111 |
3 | 222210001200211121102220211222 |
4 | 232123231121212031120033 |
5 | 203231321403140231112 |
6 | 2002154432123233555 |
7 | 61004666024466152 |
oct | 5633553146153017 |
9 | 883050747386758 |
10 | 204214313211407 |
11 | 5a083892a51754 |
12 | 1aaa21283788bb |
13 | 89c443385a935 |
14 | 386004dd6dc99 |
15 | 1892139d70372 |
hex | b9bb5998d60f |
204214313211407 has 2 divisors, whose sum is σ = 204214313211408. Its totient is φ = 204214313211406.
The previous prime is 204214313211361. The next prime is 204214313211409. The reversal of 204214313211407 is 704112313412402.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-204214313211407 is a prime.
Together with 204214313211409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (204214313211409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102107156605703 + 102107156605704.
It is an arithmetic number, because the mean of its divisors is an integer number (102107156605704).
Almost surely, 2204214313211407 is an apocalyptic number.
204214313211407 is a deficient number, since it is larger than the sum of its proper divisors (1).
204214313211407 is an equidigital number, since it uses as much as digits as its factorization.
204214313211407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 204214313211407 its reverse (704112313412402), we get a palindrome (908326626623809).
The spelling of 204214313211407 in words is "two hundred four trillion, two hundred fourteen billion, three hundred thirteen million, two hundred eleven thousand, four hundred seven".
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