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20768913437 is a prime number
BaseRepresentation
bin10011010101111011…
…000111100000011101
31222121102101010012012
4103111323013200131
5320013320212222
613312513521005
71333446565016
oct232573074035
958542333165
1020768913437
118898568078
124037573165
131c5ca950bc
14101047c00d
158185021e2
hex4d5ec781d

20768913437 has 2 divisors, whose sum is σ = 20768913438. Its totient is φ = 20768913436.

The previous prime is 20768913421. The next prime is 20768913439. The reversal of 20768913437 is 73431986702.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19538727961 + 1230185476 = 139781^2 + 35074^2 .

It is a cyclic number.

It is not a de Polignac number, because 20768913437 - 24 = 20768913421 is a prime.

It is a super-3 number, since 3×207689134373 (a number of 32 digits) contains 333 as substring.

Together with 20768913439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20768913439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10384456718 + 10384456719.

It is an arithmetic number, because the mean of its divisors is an integer number (10384456719).

Almost surely, 220768913437 is an apocalyptic number.

It is an amenable number.

20768913437 is a deficient number, since it is larger than the sum of its proper divisors (1).

20768913437 is an equidigital number, since it uses as much as digits as its factorization.

20768913437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1524096, while the sum is 50.

The spelling of 20768913437 in words is "twenty billion, seven hundred sixty-eight million, nine hundred thirteen thousand, four hundred thirty-seven".