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210002112101143 is a prime number
BaseRepresentation
bin101111101111111011101101…
…010010110011101100010111
31000112120000011021011011111001
4233233323231102303230113
5210011133311144214033
62022345345524124131
762143103051356315
oct5757735522635427
91015500137134431
10210002112101143
1160a054395a01aa
121b677996536647
139024163b8129b
1439c022946d0b5
151942984639e7d
hexbefeed4b3b17

210002112101143 has 2 divisors, whose sum is σ = 210002112101144. Its totient is φ = 210002112101142.

The previous prime is 210002112101137. The next prime is 210002112101183. The reversal of 210002112101143 is 341101211200012.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-210002112101143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 210002112101143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (210002112101113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105001056050571 + 105001056050572.

It is an arithmetic number, because the mean of its divisors is an integer number (105001056050572).

Almost surely, 2210002112101143 is an apocalyptic number.

210002112101143 is a deficient number, since it is larger than the sum of its proper divisors (1).

210002112101143 is an equidigital number, since it uses as much as digits as its factorization.

210002112101143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 210002112101143 its reverse (341101211200012), we get a palindrome (551103323301155).

The spelling of 210002112101143 in words is "two hundred ten trillion, two billion, one hundred twelve million, one hundred one thousand, one hundred forty-three".