Base | Representation |
---|---|
bin | 101111101111111011101101… |
… | …111000100100011011100111 |
3 | 1000112120000011221210002022012 |
4 | 233233323231320210123213 |
5 | 210011133321213000403 |
6 | 2022345350520224435 |
7 | 62143103231455256 |
oct | 5757735570443347 |
9 | 1015500157702265 |
10 | 210002122000103 |
11 | 60a05444141464 |
12 | 1b67799990b11b |
13 | 9024165c38b64 |
14 | 39c022a8c879d |
15 | 1942985442ed8 |
hex | befeede246e7 |
210002122000103 has 2 divisors, whose sum is σ = 210002122000104. Its totient is φ = 210002122000102.
The previous prime is 210002122000091. The next prime is 210002122000141. The reversal of 210002122000103 is 301000221200012.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 210002122000103 - 26 = 210002122000039 is a prime.
It is a super-2 number, since 2×2100021220001032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210002122003103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105001061000051 + 105001061000052.
It is an arithmetic number, because the mean of its divisors is an integer number (105001061000052).
Almost surely, 2210002122000103 is an apocalyptic number.
210002122000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
210002122000103 is an equidigital number, since it uses as much as digits as its factorization.
210002122000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 210002122000103 its reverse (301000221200012), we get a palindrome (511002343200115).
The spelling of 210002122000103 in words is "two hundred ten trillion, two billion, one hundred twenty-two million, one hundred three", and thus it is an aban number.
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