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21000410023 is a prime number
BaseRepresentation
bin10011100011101110…
…001101001110100111
32000012112222100210211
4103203232031032213
5321002101110043
613351503400251
71342260353125
oct234356151647
960175870724
1021000410023
1189a720296a
1240a0bb3087
131c98a29628
1410330dc915
1582d9cda9d
hex4e3b8d3a7

21000410023 has 2 divisors, whose sum is σ = 21000410024. Its totient is φ = 21000410022.

The previous prime is 21000410021. The next prime is 21000410051. The reversal of 21000410023 is 32001400012.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21000410023 - 21 = 21000410021 is a prime.

It is a super-2 number, since 2×210004100232 (a number of 21 digits) contains 22 as substring.

Together with 21000410021, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 21000409985 and 21000410012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21000410021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10500205011 + 10500205012.

It is an arithmetic number, because the mean of its divisors is an integer number (10500205012).

Almost surely, 221000410023 is an apocalyptic number.

21000410023 is a deficient number, since it is larger than the sum of its proper divisors (1).

21000410023 is an equidigital number, since it uses as much as digits as its factorization.

21000410023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 21000410023 its reverse (32001400012), we get a palindrome (53001810035).

The spelling of 21000410023 in words is "twenty-one billion, four hundred ten thousand, twenty-three".