Base | Representation |
---|---|
bin | 10011100011110000… |
… | …111111101111111001 |
3 | 2000012121100111211222 |
4 | 103203300333233321 |
5 | 321002243004431 |
6 | 13351531201425 |
7 | 1342266520013 |
oct | 234360775771 |
9 | 60177314758 |
10 | 21001141241 |
11 | 89a7662283 |
12 | 40a12a6275 |
13 | 1c98c243c2 |
14 | 103324d1b3 |
15 | 82dac557b |
hex | 4e3c3fbf9 |
21001141241 has 2 divisors, whose sum is σ = 21001141242. Its totient is φ = 21001141240.
The previous prime is 21001141201. The next prime is 21001141243. The reversal of 21001141241 is 14214110012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18658194025 + 2342947216 = 136595^2 + 48404^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21001141241 is a prime.
Together with 21001141243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (21001141243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10500570620 + 10500570621.
It is an arithmetic number, because the mean of its divisors is an integer number (10500570621).
Almost surely, 221001141241 is an apocalyptic number.
It is an amenable number.
21001141241 is a deficient number, since it is larger than the sum of its proper divisors (1).
21001141241 is an equidigital number, since it uses as much as digits as its factorization.
21001141241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 21001141241 its reverse (14214110012), we get a palindrome (35215251253).
The spelling of 21001141241 in words is "twenty-one billion, one million, one hundred forty-one thousand, two hundred forty-one".
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