Base | Representation |
---|---|
bin | 101111110000000100111011… |
… | …111110110101011101010111 |
3 | 1000112120221201220202100122001 |
4 | 233300010323332311131113 |
5 | 210011314110140401101 |
6 | 2022354105140020131 |
7 | 62143603455000253 |
oct | 5760047376653527 |
9 | 1015527656670561 |
10 | 210012022200151 |
11 | 60a09664591276 |
12 | 1b6798a1391647 |
13 | 90250830528b2 |
14 | 39c08c96ad263 |
15 | 1942d6468a901 |
hex | bf013bfb5757 |
210012022200151 has 2 divisors, whose sum is σ = 210012022200152. Its totient is φ = 210012022200150.
The previous prime is 210012022200017. The next prime is 210012022200157. The reversal of 210012022200151 is 151002220210012.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 210012022200151 - 211 = 210012022198103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210012022200157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105006011100075 + 105006011100076.
It is an arithmetic number, because the mean of its divisors is an integer number (105006011100076).
Almost surely, 2210012022200151 is an apocalyptic number.
210012022200151 is a deficient number, since it is larger than the sum of its proper divisors (1).
210012022200151 is an equidigital number, since it uses as much as digits as its factorization.
210012022200151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160, while the sum is 19.
Adding to 210012022200151 its reverse (151002220210012), we get a palindrome (361014242410163).
The spelling of 210012022200151 in words is "two hundred ten trillion, twelve billion, twenty-two million, two hundred thousand, one hundred fifty-one".
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