Base | Representation |
---|---|
bin | 11110100011111000111… |
… | …110010010110100000011 |
3 | 21102202210001101201121211 |
4 | 132203320332102310003 |
5 | 233402022001320003 |
6 | 4244440552030551 |
7 | 304504646661064 |
oct | 36437076226403 |
9 | 7382701351554 |
10 | 2100121120003 |
11 | 73a724693165 |
12 | 29b026392457 |
13 | 12306b1a074a |
14 | 73909a3c56b |
15 | 39967b8e96d |
hex | 1e8f8f92d03 |
2100121120003 has 2 divisors, whose sum is σ = 2100121120004. Its totient is φ = 2100121120002.
The previous prime is 2100121120001. The next prime is 2100121120037. The reversal of 2100121120003 is 3000211210012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2100121120003 - 21 = 2100121120001 is a prime.
Together with 2100121120001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2100121120001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050060560001 + 1050060560002.
It is an arithmetic number, because the mean of its divisors is an integer number (1050060560002).
Almost surely, 22100121120003 is an apocalyptic number.
2100121120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100121120003 is an equidigital number, since it uses as much as digits as its factorization.
2100121120003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2100121120003 its reverse (3000211210012), we get a palindrome (5100332330015).
Subtracting 2100121120003 from its reverse (3000211210012), we obtain a palindrome (900090090009).
The spelling of 2100121120003 in words is "two trillion, one hundred billion, one hundred twenty-one million, one hundred twenty thousand, three".
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