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2100331151 is a prime number
BaseRepresentation
bin111110100110000…
…1000001010001111
312102101010212200122
41331030020022033
513300141044101
6544225215155
7103022343302
oct17514101217
95371125618
102100331151
11988644976
124a74914bb
132761a57c9
1415cd34b39
15c45d051b
hex7d30828f

2100331151 has 2 divisors, whose sum is σ = 2100331152. Its totient is φ = 2100331150.

The previous prime is 2100331133. The next prime is 2100331153. The reversal of 2100331151 is 1511330012.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2100331151 is a prime.

It is a super-2 number, since 2×21003311512 = 8822781887721969602, which contains 22 as substring.

Together with 2100331153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2100331153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050165575 + 1050165576.

It is an arithmetic number, because the mean of its divisors is an integer number (1050165576).

Almost surely, 22100331151 is an apocalyptic number.

2100331151 is a deficient number, since it is larger than the sum of its proper divisors (1).

2100331151 is an equidigital number, since it uses as much as digits as its factorization.

2100331151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 2100331151 is about 45829.3699607577. The cubic root of 2100331151 is about 1280.6464733657.

Adding to 2100331151 its reverse (1511330012), we get a palindrome (3611661163).

The spelling of 2100331151 in words is "two billion, one hundred million, three hundred thirty-one thousand, one hundred fifty-one".