Base | Representation |
---|---|
bin | 111110100111010… |
… | …1011111011111111 |
3 | 12102102101221220021 |
4 | 1331032223323333 |
5 | 13300324030413 |
6 | 544251433011 |
7 | 103031136133 |
oct | 17516537377 |
9 | 5372357807 |
10 | 2101001983 |
11 | 988a62983 |
12 | 4a7755767 |
13 | 27637bc52 |
14 | 15d06b3c3 |
15 | c46b418d |
hex | 7d3abeff |
2101001983 has 2 divisors, whose sum is σ = 2101001984. Its totient is φ = 2101001982.
The previous prime is 2101001957. The next prime is 2101002011. The reversal of 2101001983 is 3891001012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2101001983 - 25 = 2101001951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2101005983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050500991 + 1050500992.
It is an arithmetic number, because the mean of its divisors is an integer number (1050500992).
Almost surely, 22101001983 is an apocalyptic number.
2101001983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2101001983 is an equidigital number, since it uses as much as digits as its factorization.
2101001983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The square root of 2101001983 is about 45836.6881766124. The cubic root of 2101001983 is about 1280.7828022151.
Adding to 2101001983 its reverse (3891001012), we get a palindrome (5992002995).
The spelling of 2101001983 in words is "two billion, one hundred one million, one thousand, nine hundred eighty-three".
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