Base | Representation |
---|---|
bin | 1100001110110001000… |
… | …0001100110110000111 |
3 | 202002100202210122110211 |
4 | 3003230100030312013 |
5 | 11420312224200403 |
6 | 240310113500251 |
7 | 21116010244636 |
oct | 3035420146607 |
9 | 662322718424 |
10 | 210122100103 |
11 | 811264a1893 |
12 | 34881571687 |
13 | 16a783ba416 |
14 | a25454951d |
15 | 56ebe0006d |
hex | 30ec40cd87 |
210122100103 has 2 divisors, whose sum is σ = 210122100104. Its totient is φ = 210122100102.
The previous prime is 210122100047. The next prime is 210122100121. The reversal of 210122100103 is 301001221012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 210122100103 - 221 = 210120002951 is a prime.
It is a super-3 number, since 3×2101221001033 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210122100203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105061050051 + 105061050052.
It is an arithmetic number, because the mean of its divisors is an integer number (105061050052).
Almost surely, 2210122100103 is an apocalyptic number.
210122100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
210122100103 is an equidigital number, since it uses as much as digits as its factorization.
210122100103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 210122100103 its reverse (301001221012), we get a palindrome (511123321115).
The spelling of 210122100103 in words is "two hundred ten billion, one hundred twenty-two million, one hundred thousand, one hundred three".
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