Base | Representation |
---|---|
bin | 11110100111100000111… |
… | …001001101011010111111 |
3 | 21110010211012222001112122 |
4 | 132213200321031122333 |
5 | 233433004044220221 |
6 | 4250323025153155 |
7 | 305003244530651 |
oct | 36474071153277 |
9 | 7403735861478 |
10 | 2104012101311 |
11 | 741340a85a9a |
12 | 29b93148b7bb |
13 | 12353b341653 |
14 | 73b986d46d1 |
15 | 39ae457ceab |
hex | 1e9e0e4d6bf |
2104012101311 has 2 divisors, whose sum is σ = 2104012101312. Its totient is φ = 2104012101310.
The previous prime is 2104012101251. The next prime is 2104012101313. The reversal of 2104012101311 is 1131012104012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2104012101311 - 226 = 2103944992447 is a prime.
It is a Sophie Germain prime.
Together with 2104012101313, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2104012101311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2104012101313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052006050655 + 1052006050656.
It is an arithmetic number, because the mean of its divisors is an integer number (1052006050656).
Almost surely, 22104012101311 is an apocalyptic number.
2104012101311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2104012101311 is an equidigital number, since it uses as much as digits as its factorization.
2104012101311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 2104012101311 its reverse (1131012104012), we get a palindrome (3235024205323).
The spelling of 2104012101311 in words is "two trillion, one hundred four billion, twelve million, one hundred one thousand, three hundred eleven".
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