210411323130031 has 2 divisors, whose sum is σ = 210411323130032. Its totient is φ = 210411323130030.

The previous prime is 210411323129957. The next prime is 210411323130067. The reversal of 210411323130031 is 130031323114012.

210411323130031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 210411323130031 - 2²³ = 210411314741423 is a prime.

It is a super-2 number, since 2×210411323130031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 210411323129978 and 210411323130005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (210411323130091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105205661565015 + 105205661565016.

It is an arithmetic number, because the mean of its divisors is an integer number (105205661565016).

Almost surely, 2^{210411323130031} is an apocalyptic number.

210411323130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

210411323130031 is an equidigital number, since it uses as much as digits as its factorization.

210411323130031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 210411323130031 its reverse (130031323114012), we get a palindrome (340442646244043).

The spelling of 210411323130031 in words is "two hundred ten trillion, four hundred eleven billion, three hundred twenty-three million, one hundred thirty thousand, thirty-one".