Base | Representation |
---|---|
bin | 101111110101111010011110… |
… | …010001001101000101000111 |
3 | 1000121000021222221022012222012 |
4 | 233311322132101031011013 |
5 | 210034402013401004231 |
6 | 2023302240052324435 |
7 | 62214562563515006 |
oct | 5765723621150507 |
9 | 1017007887265865 |
10 | 210413103141191 |
11 | 610537722a0675 |
12 | 1b72357661371b |
13 | 9053b415ca902 |
14 | 39d609724cc3d |
15 | 194d4dae02e2b |
hex | bf5e9e44d147 |
210413103141191 has 2 divisors, whose sum is σ = 210413103141192. Its totient is φ = 210413103141190.
The previous prime is 210413103141079. The next prime is 210413103141209. The reversal of 210413103141191 is 191141301314012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 210413103141191 - 218 = 210413102879047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210413103141491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105206551570595 + 105206551570596.
It is an arithmetic number, because the mean of its divisors is an integer number (105206551570596).
Almost surely, 2210413103141191 is an apocalyptic number.
210413103141191 is a deficient number, since it is larger than the sum of its proper divisors (1).
210413103141191 is an equidigital number, since it uses as much as digits as its factorization.
210413103141191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 32.
The spelling of 210413103141191 in words is "two hundred ten trillion, four hundred thirteen billion, one hundred three million, one hundred forty-one thousand, one hundred ninety-one".
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