Base | Representation |
---|---|
bin | 11110100111111000000… |
… | …010001100010101101101 |
3 | 21110011211021111020010021 |
4 | 132213320002030111231 |
5 | 233434302441112031 |
6 | 4250425334242141 |
7 | 305016000454162 |
oct | 36477002142555 |
9 | 7404737436107 |
10 | 2104400332141 |
11 | 741520142618 |
12 | 29ba1b4b6351 |
13 | 1235a08c2033 |
14 | 73bd40b4069 |
15 | 39b186b9511 |
hex | 1e9f808c56d |
2104400332141 has 2 divisors, whose sum is σ = 2104400332142. Its totient is φ = 2104400332140.
The previous prime is 2104400332081. The next prime is 2104400332193. The reversal of 2104400332141 is 1412330044012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1847778048900 + 256622283241 = 1359330^2 + 506579^2 .
It is a cyclic number.
It is not a de Polignac number, because 2104400332141 - 211 = 2104400330093 is a prime.
It is a super-2 number, since 2×21044003321412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2104400312141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052200166070 + 1052200166071.
It is an arithmetic number, because the mean of its divisors is an integer number (1052200166071).
Almost surely, 22104400332141 is an apocalyptic number.
It is an amenable number.
2104400332141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2104400332141 is an equidigital number, since it uses as much as digits as its factorization.
2104400332141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2104400332141 its reverse (1412330044012), we get a palindrome (3516730376153).
The spelling of 2104400332141 in words is "two trillion, one hundred four billion, four hundred million, three hundred thirty-two thousand, one hundred forty-one".
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