Base | Representation |
---|---|
bin | 1001100100100000011000… |
… | …01111011111111110001111 |
3 | 2202111221020020002202211221 |
4 | 10302100030033133332033 |
5 | 10224302234023440421 |
6 | 112432105011024211 |
7 | 4301330141046652 |
oct | 462201417377617 |
9 | 82457206082757 |
10 | 21045545140111 |
11 | 6784402636898 |
12 | 243a92659b067 |
13 | b987813bbb0b |
14 | 52a8774b9899 |
15 | 267699d1d841 |
hex | 13240c3dff8f |
21045545140111 has 2 divisors, whose sum is σ = 21045545140112. Its totient is φ = 21045545140110.
The previous prime is 21045545140079. The next prime is 21045545140187. The reversal of 21045545140111 is 11104154554012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21045545140111 - 25 = 21045545140079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21045545147111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10522772570055 + 10522772570056.
It is an arithmetic number, because the mean of its divisors is an integer number (10522772570056).
Almost surely, 221045545140111 is an apocalyptic number.
21045545140111 is a deficient number, since it is larger than the sum of its proper divisors (1).
21045545140111 is an equidigital number, since it uses as much as digits as its factorization.
21045545140111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16000, while the sum is 34.
Adding to 21045545140111 its reverse (11104154554012), we get a palindrome (32149699694123).
The spelling of 21045545140111 in words is "twenty-one trillion, forty-five billion, five hundred forty-five million, one hundred forty thousand, one hundred eleven".
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