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2104747200041 is a prime number
BaseRepresentation
bin11110101000001100101…
…101011000111000101001
321110012201110011221102112
4132220030231120320221
5233441010240400131
64250524005012105
7305030412004643
oct36501455307051
97405643157375
102104747200041
11741688a18602
1229bab76b4035
1312362771c705
1473c281a7893
1539b38d8502b
hex1ea0cb58e29

2104747200041 has 2 divisors, whose sum is σ = 2104747200042. Its totient is φ = 2104747200040.

The previous prime is 2104747199981. The next prime is 2104747200043. The reversal of 2104747200041 is 1400027474012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1685582890000 + 419164310041 = 1298300^2 + 647429^2 .

It is a cyclic number.

It is not a de Polignac number, because 2104747200041 - 218 = 2104746937897 is a prime.

It is a super-4 number, since 4×21047472000414 (a number of 50 digits) contains 4444 as substring.

Together with 2104747200043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2104747199980 and 2104747200007.

It is not a weakly prime, because it can be changed into another prime (2104747200043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052373600020 + 1052373600021.

It is an arithmetic number, because the mean of its divisors is an integer number (1052373600021).

Almost surely, 22104747200041 is an apocalyptic number.

It is an amenable number.

2104747200041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2104747200041 is an equidigital number, since it uses as much as digits as its factorization.

2104747200041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12544, while the sum is 32.

The spelling of 2104747200041 in words is "two trillion, one hundred four billion, seven hundred forty-seven million, two hundred thousand, forty-one".