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21055433701 is a prime number
BaseRepresentation
bin10011100111000000…
…000110101111100101
32000100101111212002211
4103213000012233211
5321110142334301
613401151003421
71343526143041
oct234700065745
960311455084
1021055433701
118a25274a85
1240b7509571
131ca7253513
14103a543021
1583374c051
hex4e7006be5

21055433701 has 2 divisors, whose sum is σ = 21055433702. Its totient is φ = 21055433700.

The previous prime is 21055433677. The next prime is 21055433747. The reversal of 21055433701 is 10733455012.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14592881601 + 6462552100 = 120801^2 + 80390^2 .

It is a cyclic number.

It is not a de Polignac number, because 21055433701 - 27 = 21055433573 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21055433801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10527716850 + 10527716851.

It is an arithmetic number, because the mean of its divisors is an integer number (10527716851).

Almost surely, 221055433701 is an apocalyptic number.

It is an amenable number.

21055433701 is a deficient number, since it is larger than the sum of its proper divisors (1).

21055433701 is an equidigital number, since it uses as much as digits as its factorization.

21055433701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12600, while the sum is 31.

Adding to 21055433701 its reverse (10733455012), we get a palindrome (31788888713).

The spelling of 21055433701 in words is "twenty-one billion, fifty-five million, four hundred thirty-three thousand, seven hundred one".