Base | Representation |
---|---|
bin | 1001100110000110000000… |
… | …00010001001000000000111 |
3 | 2202201011001022211221200011 |
4 | 10303003000002021000013 |
5 | 10231201001343111313 |
6 | 112513130323331051 |
7 | 4305301114326406 |
oct | 463030002110007 |
9 | 82634038757604 |
10 | 21100101144583 |
11 | 67a555902149a |
12 | 2449411220a87 |
13 | ba0967013776 |
14 | 52d370d3363d |
15 | 268cde66593d |
hex | 1330c0089007 |
21100101144583 has 2 divisors, whose sum is σ = 21100101144584. Its totient is φ = 21100101144582.
The previous prime is 21100101144541. The next prime is 21100101144593. The reversal of 21100101144583 is 38544110100112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21100101144583 - 233 = 21091511209991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21100101144593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550050572291 + 10550050572292.
It is an arithmetic number, because the mean of its divisors is an integer number (10550050572292).
Almost surely, 221100101144583 is an apocalyptic number.
21100101144583 is a deficient number, since it is larger than the sum of its proper divisors (1).
21100101144583 is an equidigital number, since it uses as much as digits as its factorization.
21100101144583 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 31.
Adding to 21100101144583 its reverse (38544110100112), we get a palindrome (59644211244695).
The spelling of 21100101144583 in words is "twenty-one trillion, one hundred billion, one hundred one million, one hundred forty-four thousand, five hundred eighty-three".
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