Base | Representation |
---|---|
bin | 111110111000100… |
… | …0011101001101101 |
3 | 12110001100201100002 |
4 | 1331301003221231 |
5 | 13310130341023 |
6 | 545212514045 |
7 | 103200543344 |
oct | 17561035155 |
9 | 5401321302 |
10 | 2110012013 |
11 | 99305728a |
12 | 4aa77b925 |
13 | 2781b5025 |
14 | 160334b5b |
15 | c5393b28 |
hex | 7dc43a6d |
2110012013 has 2 divisors, whose sum is σ = 2110012014. Its totient is φ = 2110012012.
The previous prime is 2110011983. The next prime is 2110012043. The reversal of 2110012013 is 3102100112.
It is a balanced prime because it is at equal distance from previous prime (2110011983) and next prime (2110012043).
It can be written as a sum of positive squares in only one way, i.e., 1510643689 + 599368324 = 38867^2 + 24482^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110012013 - 216 = 2109946477 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2110011985 and 2110012003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110012043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055006006 + 1055006007.
It is an arithmetic number, because the mean of its divisors is an integer number (1055006007).
Almost surely, 22110012013 is an apocalyptic number.
It is an amenable number.
2110012013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110012013 is an equidigital number, since it uses as much as digits as its factorization.
2110012013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
The square root of 2110012013 is about 45934.8670728457. The cubic root of 2110012013 is about 1282.6110464994.
Adding to 2110012013 its reverse (3102100112), we get a palindrome (5212112125).
The spelling of 2110012013 in words is "two billion, one hundred ten million, twelve thousand, thirteen".
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