Base | Representation |
---|---|
bin | 11110101101000110100… |
… | …001110011111111000101 |
3 | 21110201022101020012212122 |
4 | 132231012201303333011 |
5 | 234032301111224031 |
6 | 4253154244255325 |
7 | 305305032604352 |
oct | 36550641637705 |
9 | 7421271205778 |
10 | 2110012211141 |
11 | 74393a98134a |
12 | 2a0b269a1545 |
13 | 123c864483b3 |
14 | 741a7531629 |
15 | 39d461d847b |
hex | 1eb46873fc5 |
2110012211141 has 2 divisors, whose sum is σ = 2110012211142. Its totient is φ = 2110012211140.
The previous prime is 2110012211129. The next prime is 2110012211261. The reversal of 2110012211141 is 1411122100112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1987970282116 + 122041929025 = 1409954^2 + 349345^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2110012211141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110012211941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055006105570 + 1055006105571.
It is an arithmetic number, because the mean of its divisors is an integer number (1055006105571).
Almost surely, 22110012211141 is an apocalyptic number.
It is an amenable number.
2110012211141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110012211141 is an equidigital number, since it uses as much as digits as its factorization.
2110012211141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 2110012211141 its reverse (1411122100112), we get a palindrome (3521134311253).
The spelling of 2110012211141 in words is "two trillion, one hundred ten billion, twelve million, two hundred eleven thousand, one hundred forty-one".
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